![]() Students.student_id=invoice.student_id)A LEFT JOIN invoice AS B ONĪ.student_id=B.student_id AND A.invoice_set=B.invoice_set AND Invoice, students WHERE product_id = '$course_id' AND product_type = Students.student_id, invoice_date, invoice_set, invoice_id, last_name,įirst_name, addon_last_name, addon_first_name, invoice.gender FROM Of if or how many matches there are on the right side.Ī.student_id, A.invoice_date, A.invoice_set, A.last_name, A.first_name,Ī.addon_last_name, A.addon_first_name, A.gender, B.arrived,ī.invoice_id AS arrived_invoice_id, A.invoice_id FROM (SELECT * FROM What I need isįor the query to return one row for a match on the left side, regardless ![]() Returns multiple rows if there is more than one match on the right side.ĭISTINCT and GROUP BY can’t be used on the right side. In my left join query, the queryĬorrectly returns a row if there is no match on the right side, but it More than one accommodation (because they are going to move from one ![]() Identifies those who are marked as “arrived” based on theirĪccommodation (room at the retreat). This is a query that returns the students registered for a course, and ![]()
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